Question

Hi guys really need help w/ this problem will give brainllest for the first person

A pile of coins, consisting of nickels, dimes, and quarters, is worth $4.55. There are 4 more dimes than nickels and 3 quarters more than dimes. How many of each are there?

Answer 1

Answer:

There are 6 nickels, 10 dimes and 13 quarters.

Step-by-step explanation:

number of nickels = n

number of dimes = n+4

number of quarters = (n+4)+3 = n+7

express total amount in cents $4.55 = 455 cents

express total in cents by multiplying quantities of coins by value and adding them up.

455 = 5*n + 10*(n+4) + 25*(n+7) 455 = 5n + 10n + 40 + 25n + 175 240 = 40n n = 6

so number of nickels = 6.

number of dimes = number of nickels + 4 = 6+4 =10

number of quarters = number of dimes + 3 = 10+3 = 13

There are 6 nickels, 10 dimes and 13 quarters.

Answer 2

Answer:

Step-by-step explanation:

dime = 10 cents = 0.10 dollars

quarter 25 cents=0,25 dollars

nickel = 5 cents = 0.05 nickel

o.10 d +0.25 q+0.05 n=4.55 or

10d+25 q+5 n =455

d=4+n

q=d+3

q=4+n+3 ( d=n+4)

q=n+7

10d+25 q+5 n =455 ( substitute d with n+4 and q with n+7)

10(n+4)+25(n+7)+5n = 455

10n+40+25n+175+5n=455

40 n =455-215

n=6 ( six nickels)

d=4+n

dime=10 pieces

uarter = n+7

quarter = 13 pieces

check :

10d+25 q+5 n =455

10(10)+25(13)+5(6)=455