Question

To the nearest tenth of a second, how long after the pebble falls will it hit the ground? More information is attached in the image below ::::)

Answer 1

Answer:

First part is h(t)=-4.9t^2+60, second part is 3.5

Step-by-step explanation:

Answer 2

After 3.5 seconds the pebble will hit the ground.

What is a quadratic equation?

"It is an equation of the form $ax^{2} +bx+c=0$, where a, b, c are real numbers and a ≠ 0."

For given question,

The function $h(t)=-4.9t^2+h_0$ represents the height of an object after it falls from the height $h_0$

Here, $h_0=60$ meters

We have the quadratic equation,

$h(t)=-4.9t^2+60$

When the pebble will hit the ground, then $h(t)=0$

So the quadratic equation becomes,

$\Rightarrow 0=-4.9t^2+60\\\\\Rightarrow 4.9t^2=60\\\\\Rightarrow t^2=12.24\\\\\Rightarrow t=3.49\\\\\Rightarrow t=3.5~~seconds$

Therefore, after 3.5 seconds the pebble will hit the ground.

Learn more about the quadratic equation here:

https://brainly.com/question/1863222

#SPJ2