Question

The mass of a fully loaded Boeing 747 is abput 4,082,331.33 kg. If it is cruising eastward at a velocity of 253 m/s, what is its momentum? ​

Answer 1

Answer:

1,032,829,826.49kgm/s

Explanation:

Momentum is defines as the product of mas of a body and its velocity,

Given

Mass of Being 747 =

Velocity = 253m/s

Required

Momentum of the body

Substituting the required value into the formula;

Momentum = 4,082,331.33 kg * 253

Momentum = 1,032,829,826.49 kgm/s

Therefore the momentum of the body is 1,032,829,826.49kgm/s

Answer 2

The momentum of fully loaded Boeing 747 is  $1.032 \times 10^{9} \;\rm kg.m/s$.

Given data:

The mass of fully loaded Boeing 747 is, m = 4,082,331.33 kg.

The velocity of cruising is, v = 253 m/s.

The concept of momentum says that the impact created by the applied force is known as momentum. It is expressed as product of mass and velocity.

Then the expression is,

p = mv

Soling as,

$p = 4,082,331.33 \times 253\\\\p=1.032 \times 10^{9} \;\rm kg.m/s$

Thus, we can conclude that the momentum of fully loaded Boeing 747 is $1.032 \times 10^{9} \;\rm kg.m/s$.

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