The surface area of the rectangular prism with dimensions [tex]2[/tex] cm by [tex]2[/tex]cm by [tex]5[/tex] cm is [tex]48 cm^2.[/tex]
The surface area of a rectangular prism is [tex]2(lw+wh+lh)[/tex], where [tex]l[/tex] is length, [tex]w[/tex] is width, and [tex]h[/tex] is height.
A rectangular prism has dimensions of [tex]2[/tex] cm by [tex]2[/tex] cm by [tex]5[/tex] cm.
Let [tex]l=2[/tex] cm, [tex]w=2[/tex] cm and [tex]h=5[/tex] cm.
So, surface area [tex]= 2(lw+wh+lh)[/tex]
[tex]= 2 (2 \times 2 + 2 \times 5 + 2 \times 5)[/tex]
[tex]= 2 (4 + 10 + 10)[/tex]
[tex]= 2 (24)[/tex]
[tex]= 48 cm^2.[/tex]
So, the surface area of the rectangular prism is [tex]48 cm^2[/tex].
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