Question

The density of water at 4 o C is known to be 1.00 g/mL. Kayla experimentally found the density of water to be 1.075 g/mL. What is the error of Kayla’s measurement? Calculate the percent error.

Answer 1

Answer:

7.5%

Explanation:

Percent error is this formula: your answer - accepted value divided by accepted value x 100

1.075 g/mL - 1.00 g/mL = 0.075

Divide 0.075 by 1.00 g/mL = 0.075

Multiply 0.075 by 100 = 7.5

Answer 2

The percent of the error in Kayla's density measurement is 7.5%.

The given parameters;

• known density of water, ρ = 1 g/mL
• measured density of water, ρ = 1.075 g/mL

The error in Kayla measurement is calculated as follows;

Error = measured value - known value

Error = 1.075 g/ml - 1 g/ml

Error = 0.075 g/ml

The percent of the error in Kayla's density measurement is calculated as;

$Error \ percent = \frac{Error}{known \ value} \times 100\%\\\\Error \ percent = \frac{0.075}{1} \times 100\%\\\\Error \ percent = = 7.5\%$

Thus, the percent of the error in Kayla's density measurement is 7.5%.

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