Given:
Sum of two consecutive integers is 325.
To find:
The number that is the least of the two consecutive integers.
Solution:
Let the two consecutive integers are x and x+1. So,
[tex]x+(x+1)=325[/tex]
[tex]2x+1=325[/tex]
Subtract 1 from both sides.
[tex]2x=324[/tex]
Divide both sides by 2.
[tex]x=\dfrac{324}{2}[/tex]
[tex]x=162[/tex]
The second integer is
[tex]x+1=162+1=163[/tex]
Since [tex]162<163[/tex], therefore, the least of the two consecutive integers is 162.