Question

The Hawaiian language has 12 letters: five vowels and seven consonants. Each of the 12 Hawaiian letters are written on a slip of paper and placed in the bag. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag.


What is the probability that two vowels are chosen?


StartFraction 5 Over 72 EndFraction

StartFraction 25 Over 144 EndFraction

StartFraction 7 Over 12 EndFraction

Five-sixths

Answer 1

Answer:

$\frac{25}{144}$

Step-by-step explanation:

Given: The Hawaiian language has 12 letters: five vowels and seven consonants. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag.

To find: probability that two vowels are chosen

Solution:

Probability that a vowel is chosen = number of favourable outcomes/ Total number of outcomes

$=\frac{5}{12}$

If a letter is randomly chosen from the bag and then replaced and then, a second letter is randomly chosen from the bag,

Probability that two vowels are chosen = probability that the first letter is a vowel × probability that the second letter is a vowel such that first letter is  replaced $=(\frac{5}{12} )(\frac{5}{12} )$

$=\frac{25}{144}$

Answer 2

Answer:

B. 25/144

Step-by-step explanation: