Answer:
The number of electrons per second received by the panel is 2.19 x 10²¹ electrons/second
Explanation:
Given;
intensity of light, I = 225 W/m²
area of the solar panel, A = 2m x 6m = 12m²
Power of photons hitting the panel = 225 W/m² x 12m² = 2700 W
Power received by the electrons in the panel = 0.13 x 2700 W = 351 W
Energy of these electrons = 351 J/s
The number of electrons per second is given by;
[tex]= \frac{1 \ electron}{1.602*10^{-19} \ J} *\frac{351 \ J}{s} = 2.19*10^{21} \ electrons/second[/tex]
Therefore, the number of electrons per second received by the panel is 2.19 x 10²¹ electrons/second