Question

What mass of glucose (C6H12O6) is needed to prepare 200.0 ml of a 2.50 M glucose solution?

Answer 1

Molar mass glucose ( C6H12O6 ) = 180 g/mol

Volume in liters: 200.0 mL / 1000 => 0.2 L

Molarity = 2.50  M

1 L ----------------- 2.50
0.2 L -------------- ?

0.2 x 2.50 / 1 => 0.5 moles

1 mole ------------- 180 g
0.5 moles --------- ?

0.5 x 180 / 1 => 90 g of glucose

hope this helps!