Answer:
Theoretical yield is 2.92g TiO₂
Explanation:
The reaction of Ti with O₂ to produce TiO₂ is:
Ti + O₂ → TiO₂
First, we need to find moles of titanium and oxygen. As the reaction is 1:1, we can determine directly the limiting reactant, the theoretical moles of TiO₂ and thus, theoretical yield:
Moles Ti (molar mass: 47.867g/mol):
1.75g * (1mol / 47.867g) = 0.03656 moles Ti
Moles O₂ (molar mass: 32g/mol):
1.25g * (1mol / 32g) = 0.0390 moles O₂
That means only 0.03656 moles of Ti will react withe 0.03656 moles of O₂ producing 0.03656 moles of TiO₂
As molar mass of TiO₂ is 79.866g/mol, the theoretical yield of the product is:
0.03656 moles TiO₂ * (79.866g / mol) = 2.92g TiO₂
The theoretical yield of the reaction of titanium and oxygen has been 2.92 grams.
The balanced reaction for the reaction of Titanium with oxygen can be given as:
[tex]\rm Ti\;+\;O_2\;\rightarrow\;TiO_2[/tex]
According to the balanced equation, 1 mole of Ti gives 1 mole of Titanium oxide.
The moles of Ti can be given as:
Moles = [tex]\rm \dfrac{mass}{molecular\;mass}[/tex]
The molecular mass of Ti has been 47.867 grams.
Moles of Ti has been:
Moles of Ti = [tex]\rm \dfrac{1.75}{47.867}[/tex]
Moles of Ti = 0.036 mol.
Moles of Oxygen has been:
Moles of oxygen = [tex]\rm \dfrac{1.25}{32}[/tex]
Moles of oxygen = 0.0390 mol.
The moles of Ti has been less than the required moles of Ti for the complete utilization of oxygen, thus titanium has been the limiting reactant.
1 mole of Titanium = 1 mole of titanium oxide
0.036 mol of Titanium = 0.036 mol of titanium oxide
The mass of 0.036 mol titanium oxide has been:
Mass = moles × molecular weight
Mass of titanium oxide = 0.036 mol × 79.866 g/mol
Mass of titanium oxide = 2.92 grams.
The theoretical yield of the reaction of titanium and oxygen has been 2.92 grams.
For more information about the theoretical yield, refer to the link:
https://brainly.com/question/7786567
