Question

if p(x)=2(x^2+1)+16, what is the value of p(12)?​

Answer 1

Answer: P(12)=306

Step-by-step explanation:

Replace the ‘x’ with 12 in the equation. 2(12^2+1)+16

2•144+1+16 (distribute the 2)

288+2+16

306

Answer 2

Step-by-step explanation:

Hey there!

Given;

p(x)= 2(x^2+1)+16

And p(x)= 12

Now,

Putting value of p(12) in p(x)= 2(x^2+1)+16.

$p(12) = 2( {12}^{2} + 1) + 16$

$p(12) = 290 + 16$

Therefore p(12)= 306.

Hope it helps...