Answer:
The domain of the function b(s) is
[tex]s\in[0,150][/tex]
Step-by-step explanation:
Given that, a total of 560 books is added to the book shelf each morning.
[tex]s[/tex] be the number of the students who visit the library on a particular day and takes exactly 3 books from this shelf.
So, the number of books they take from the shelf is 3s.
The number of remaining books the shelf [tex]=560-3s[/tex].
As , given that [tex]b[/tex] be the number of books left on the shelf at the end of that day, so the required function, [tex]b(s)[/tex], is
[tex]b=560-3s\;\cdots(i)[/tex]
As there are 150 students in the school. So, if no one will go to the library, than [tex]s=0[/tex] which is the minimum value, and if all goes to the library , than [tex]s=150[/tex] which is the maximum value of [tex]s[/tex].
So, the possible value of s is:
[tex]0\leq s\leq150\;\cdots(ii)[/tex]
Now, as there is no book left or there are some books left the negative value of [tex]b[/tex] is not possible. So,
[tex]b\geq0[/tex]
[tex]\Rightarrow 560-3s\geq0[/tex] [fron equation (i)]
[tex]\Rightarrow s\leq 560/3[/tex]
[tex]\Rightarrow s\leq 186\frac{2}{3}[/tex]
as s id the number of students which cant be a fractional value, so the possible nearest value is,
[tex]s\leq 186\;\cdots(iii)[/tex]
From the equations (ii) and (iii), the domain of the function [tex]b(s)[/tex] is
[tex]s\in[0,150][/tex]