Answer:
Explanation:
So, we have three consecutive positive integers.
Let the first one be x, the second be x + 1, and the third x + 2 :)
Now, we know that x(x + 1) = 11(x+2) - 22
So, let's solve this!
x(x + 1) = 11(x + 2) - 22
x^2 + x = 11x + 22 - 22
x^2 + x = 11x
x^2 - 10x = 0
A solution to this problem is x = 10, which is the smallest side :)
(Please feel free to ask how I answered this question, if you don't understand the solution!)