Write an equation of the line perpendicular to the given line that contains P.
P(3. – 5); y = 3x+2
Write an equation for the line in point-slope form.
(Simplify your answer. Use integers or fractions for any numbers in the equation.)

Respuesta :

Answer:

  y +5 = -1/3(x -3)

Step-by-step explanation:

The slope of the given line is 3. The slope of the perpendicular line is the negative reciprocal of that, -1/3. Then the point-slope equation is ...

  y -y1 = m(x -x1) . . . . line with slope m through point (x1, y1)

  y -(-5) = -1/3(x -3)

  y +5 = -1/3(x -3)

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