Answer:
No, the student is incorrect.
Step-by-step explanation:
First we need to find the x-intercept. You can do so by solving for the variable x, and letting y = 0.
The x-intercept of the graph of [tex]x+2y=5[/tex] is at [tex](5,\ 0)[/tex], because the formula for a point on a graph is [tex](x, \ y)[/tex], where the x-value comes first.
The x-value is 5, and the y-value is 0, because that is what we substituted into the equation.
In other words, when the graph touches the x-axis at 5 (5, 0), the y-value of this point of intersection will be 0.
This student is NOT correct because the point they give (0, 5) is flipped from the correct x-intercept.