Respuesta :

Answer:  15

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Work Shown:

[tex](g \circ f)(x) = g(f(x))\\\\g(x) = x^2-1\\\\g(f(x)) = (f(x))^2-1\\\\g(f(x)) = (5x-4)^2-1\\\\g(f(0)) = (5*0-4)^2-1\\\\g(f(0)) = (-4)^2-1\\\\g(f(0)) = 16-1\\\\g(f(0)) = 15\\\\(g \circ f)(0) = 15[/tex]

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