Question

4. A car accelerates uniformly from rest at 3.2 m/s^.
When the car has traveled a distance of 40.
meters, its speed will be
(1) 8.0 m/s
(2) 12.5 m/s
(3) 16 m/s
(4) 128 m/s

Answer 1

Answer:

A

Explanation:

Answer 2

The final speed of the car is: (3) 16 m/s.

Given the following data:

• Initial speed = 0 m/s (since it accelerated from rest).

• Acceleration = 3.2 $m/s^2$

• Distance = 40 meters.

To find the final speed of the car, we would use the third equation of motion;

$V^2 = U^2 + 2aS$

Where:

• V is the final speed.

• U is the initial speed.

• a is the acceleration.

• S is the distance covered.

Substituting the given parameters into the formula, we have;

$V^2 = 0^2 + 2(3.2)(40)$

$V^2 = 2$ × $3.2$ × $40$

$V^2 = 256\\\\V = \sqrt{256}$

Final speed, V = 16 m/s

Therefore, the final speed of the car is 16 m/s.

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