Question

A car accelerates from 28m/s to 42m/s. The acceleration rate
is 3.5m/s2. How much time did it take for the car to accomplish
this?

Answer 1

Answer:

t = 4 seconds

Explanation:

Given that,

Initial speed, u = 28 m/s

Final speed, v = 42 m/s

Acceleration, a = 3.5 m/s²

We need to find time taken by the car. So, using the first equation of motion as follows :

v=u+at

$t=\dfrac{v-u}{a}\\\\t=\dfrac{42-28}{3.5}\\\\t=4\ s$

So, he will need 4 seconds to accomplish this.