Question

What is the acceleration of a racing car if it’s speed is increased uniformly form 44m/s to 66 m/s over an 11 sec. period.

Answer 1

Answer:

$a=2\ m/s^2$

Explanation:

Given that,

Initial velocity, u = 44 m/s

Final velocity, v = 66 m/s

Time, t = 11 s

Acceleration = rate of change of velocity

$a=\dfrac{v-u}{t}\\\\a=\dfrac{66-44}{11}\\\\a=2\ m/s^2$

So, the acceleration of the car is $2\ m/s^2$.