Question

14. Given: 5x + 4y = 24, x + 7y= 11; Prove: y= 1
Statements
reasons

Answer 1

Answer:

Step-by-step explanation:

We can use the process of elimination as

5x + 4y = 24

5(x + 7y = 11) —>          5x + 35y = 55

5x + 4y = 24

-(5x + 35y = 55)

—————————

-31y = -31

-31y/-31 = -31/-31

y=1

Answer 2

Simultaneous equations are equations containing two sets of expressions and two unknown.

The value of y if x + 4y = 24 and x + 7y= 11 according to the question is 1

Given the simultaneous equation

5x + 4y = 24 ........... 1

x + 7y= 11 ..............2

We are to show that y = 1

Using the substituting method;

From equation 2, x = 11 - 7y ................ 3

Substitute equation 3 into 1;

5(11-7y) + 4y = 24

55 - 35y + 4y = 24

55 - 31y = 24

-31y = 24 - 55

-31y = -31

y = 31/31

y = 1

This shows that the value of y if x + 4y = 24 and x + 7y= 11 is 1

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