Question

Two consecutive integers are such that 7 times the biggest and then added to the smallest equals
495, what are they?

Answer 1

Answer:

61,62

Step-by-step explanation:

Let the smallest  number be x

Hence, the biggest number = x+1 [as it consecutive]

Hence,

7(x+1)+x=495

7x+7+x+495

8x=495-7

8x=488

x=61

Hence, smaller number=61, bigger number=62