Respuesta :

Answer:

[tex] \huge{ \fbox{ \sf{ \: ( \: 2 \:, 3 \: )}}}[/tex]

Step-by-step explanation:

[tex] \star{ \sf{ \: \: Let \: the \: points \: be \: A \: and \: B}} : [/tex]

[tex] \star{ \sf{ \: Let \: A( - 2 \:, 2 \: ) \: be \: (x1 \:, y1) \: and \: B \: ( \: 6 \:, 4 \: ) \: be \: (x2 \:, y2)}}[/tex]

[tex] \underline{ \sf{Finding \: the \: midpoint}} : [/tex]

[tex] \boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} ,\: \frac{y1 + y2}{2} )}}[/tex]

[tex] \mapsto{ \sf{Midpoint = ( \frac{ - 2 + 6}{2} \,, \frac{2 + 4}{2} }})[/tex]

[tex] \underline{ \text{Remember!}} [/tex]

  • The positive integers are always added and posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.

[tex] \mapsto{ \sf{Midpoint = ( \frac{4}{2} ,\: \frac{6}{2} )}}[/tex]

[tex] \mapsto{ \sf{Midpoint = ( \: 2 ,\: 3)}}[/tex]

Hope I helped!

Best regards! :D

~[tex] \text{TheAnimeGirl}[/tex]

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