Question

I need help!


Triangle ABC with vertices A(0,7), B(7,3),and C(1,4): (x, y) - (x - 3, y-4)
A’
B’
C’

Answer 1

Answer:

This is the correct answer

Step-by-step explanation:

The explanation is on the photo.

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Answer 2

The required vertices are $A'(-3,3), B'(4,-1), C'(-2,0)$.

Important information:

• The vertices of a triangle A(0,7), B(7,3),and C(1,4).
• Rule of translation is $(x,y)\to (x-3,y-4)$.

We need to find the vertices of triangle A'B'C'.

Translation:

Using the given rule, we get

$A(0,7)\to A'(0-3,7-4)$

$A(0,7)\to A'(-3,3)$

$B(7,3)\to B'(7-3,3-4)$

$B(7,3)\to B'(4,-1)$

$C(1,4)\to C'(1-3,4-4)$

$C(1,4)\to C'(-2,0)$

Thus, the required vertices are $A'(-3,3), B'(4,-1), C'(-2,0)$.

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