Answer:
a) = 0.65
b) = 0.5
c) = 0.7
Step-by-step explanation:
a)
First, using either A1 detected the object or A2 detected it or both did, the probability that the object is detected can be determined by any of it
so
P( probability that object is detected) = (p1 * q2) + (p2 * q1) + (p1 * p2)
so we substitute
P( probability that object is detected = (0.5 * 0.7) + (0.3 * 0.5) + (0.5 * 0.3)
= 0.65
b)
probability that object is detected by exactly 1 of the radar prototypes.
P( object is detected by exactly one of the radar prototypes ) = (p1 * q2) + (p2*q1)
= (0.5*0.7) + (0.3*0.5)
= 0.5
c)
probability that A1 that detected it.
using the Bayes theorem,
P(detected by A1 / detected by exactly one of the prototypes) = (p1 * q2) / (p1 * q2 + p2*q1) = (0.5 * 0.7) / (0.5 * 0.7) + (0.3 * 0.5)
= 0.35 / 0.5
= 0.7