Answer:
m³/(kg⋅s²)
Explanation:
Hello.
In this case, since the involved formula is:
[tex]F=G*\frac{m_1m_2}{r^2}[/tex]
By writing a dimensional analysis with the proper algebra handling, we obtain:
[tex]N[=]G*\frac{kg*kg}{m^2}\\ \\kg*\frac{m}{s^2}[=]G *\frac{kg*kg}{m^2}\\\\G[=]\frac{kg*m*m^2}{kg^2*s^2}\\ \\G[=]\frac{m^3}{kg*s^2}[/tex]
Thus, answer is:
m³/(kg⋅s²)
Note that the [=] is used to indicate the units of G.
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