Given a Rectangular piece of paper 11cm × 4cm is folded without overlapping to make a cylinder of height 4 cm
The length of the paper becomes the circumference of the base of the cylinder and width becomes height.
Let radius of the cylinder= r and height= h
Circumference of the base of cylinder = 2πr = 11cm
⇒2× 22/7 × r = 11
∴r= 7/4 cm
Now h = 4cm
Volume of the cylinder (V)=πr^2h
= 22/7 × 7/4 × 7/4 × 4cm^3
= 38.5cm
