Respuesta :

Answer:

[tex]y=-\frac{3}{4}x-\frac{7}{2}[/tex]

Step-by-step explanation:

To find the equation of a line that passes through the points (-10, 4) and (2, -5), let's first find the slope.

The formula for slope is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Let's let (-10, 4) be (x₁, y₁) and let's let (2, -5) be (x₂, y₂). Substitute this into the slope formula:

[tex]m=\frac{-5-4}{2-(-10)}[/tex]

Simplify:

[tex]m=\frac{-5-4}{2+10}[/tex]

Add or subtract:

[tex]m=-9/12[/tex]

Reduce:

[tex]m=-3/4[/tex]

Now that we know the slope, we can use the point-slope form to find the equation of our line. The point-slope form is:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and (x₁, y₁) is a point.

Let's substitute -3/4 for m. Let's also use (-10, 4) be (x₁, y₁) for consistency. So:

[tex]y-4=-\frac{3}{4}(x-(-10))[/tex]

Simplify:

[tex]y-4=-\frac{3}{4}(x+10)[/tex]

Distribute:

[tex]y-4=-\frac{3}{4}x-\frac{30}{4}[/tex]

Add 4 to both sides:

[tex]y=-\frac{3}{4}x-\frac{30}{4}+\frac{16}{4}[/tex]

Add:

[tex]y=-\frac{3}{4}x-\frac{14}{4}[/tex]

Reduce:

[tex]y=-\frac{3}{4}x-\frac{7}{2}[/tex]

And that's our equation.

And we're done!

x= (-10,4) and x= (2, -5)

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