Answer:
C₁ = 34.8 μF
C₂ = 0.2 μF
Explanation:
When the capacitors are connected in series their resultant capacitance is given by the formula:
Cs = 1/C₁ + 1/C₂
where,
Cs = Series equivalent capacitance = 4.8 μF
C₁ = Capacitance of 1st Capacitor
C₂ = Capacitance of 2nd Capacitor
Therefore,
4.8 μF = 1/C₁ + 1/C₂
(4.8 μF)(C₁ C₂) = C₁ + C₂ --------------- equation 1
When the capacitors are connected in parallel their resultant capacitance is given by the formula:
Cp = C₁ + C₂
where,
Cp = Parallel equivalent capacitance = 35 μF
Therefore,
35 μF = C₁ + C₂ -------------- equation 2
solving equation 1 and equation 2 simultaneously, we get:
C₁ = 34.8 μF
C₂ = 0.2 μF
