Answer:
45.165× 10²³ NH₄⁺ ions
Explanation:
Given data:
Number of NH₄⁺ ions present = ?
Moles of (NH₄)₃PO₄ = 2.5 mol
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole of (NH₄)₃PO₄ = 3 mole NH₄⁺
In 2.5 moles of (NH₄)₃PO₄ = 2.5× 3 = 7.5 moles of NH₄⁺
Number of ions of NH₄⁺ in 2.5 moles of (NH₄)₃PO₄:
7.5 mole of NH₄⁺ × 6.022 × 10²³ NH₄⁺ ions / 1 mol
45.165× 10²³ NH₄⁺ ions
