A line has a slope of Negative four-fifths. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options.

(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)

The slopes of the lines that are perpendicular to each other are negative reciprocal to each other, that is, is the slope of one is 4, the slope of the other would be -1/4.

Slope = change in y/change in x

Slope of the line that lie between (–2, 0) and (2, 5):

Slope = (5 - 0)/(2 - (-2)) = 5/4

Slope of the line that lie between (2, –1) and (10, 9):

Slope = (9 -(-1))/(10 - 2) = 10/8 = 5/4

The negative reciprocal of -4/5 is 5/4.

Therefore, the ordered pairs of the points on a line that is perpedicular to a line with a slope of -4/5 are:

A. (–2, 0) and (2, 5)

E. (2, –1) and (10, 9)

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A line has a slope of Negative four-fifths. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options. (–2, 0) and (2, 5) (–4, 5) and (4, –5) (–3, 4) and (2, 0) (1, –1) and (6, –5) (2, –1) and (10, 9)

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What is the Slope of Perpendicular Lines?

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A line has a slope of Negative four-fifths. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options.

(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)