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In a statistics class, there are 22 juniors and 18 seniors. Of the juiors, 12 are females. Of the seniors, 11 are males. What is the probability that a randomly selected studemt from the class is a male or a junior?

Respuesta :

Answer:

a) 0.857

b) 0.571

c) 1

Step-by-step explanation:

Based on the data given, we have

18 juniors

10 seniors

6 female seniors

10-6 = 4 male seniors

12 junior males

18-12 = 6 junior female

6+6 = 12 female

4+12 = 16 male

A total of 28 students

The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have

P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857

P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571

P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1

Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.

The probability that a randomly selected student from the class is a male or a junior = 33/40 or 0.825

What is the probability of an event?

The probability of an event is a fractional value representing the chance of the event taking place. The probability of event A can be determined by the ratio of the number of outcomes favorable to event A, to the total number of outcomes.

How do we solve the given question?

We are informed that in a statistics class, there are 22 juniors and 18 seniors. Of the juniors, 12 are females. Of the seniors, 11 are males.

We are asked to find the probability that a randomly selected student from the class is a male or a junior.

To find the probability, we first need to find the number of juniors or males in the class.

The number of juniors = 22.

The number of males = (22-12) + 11 = 10 + 11 = 21 {Taking (22 - 12) as there are 12 females among the 22 juniors}

Now, we have counted male juniors in both cases.

The number of male juniors = 22 - 12 = 10.

∴ Total number of favorable outcomes = The number of juniors + The number of males - The number of male juniors = 22 + 21 - 10 = 33.

Total number of outcomes = Total students = 22 + 18 = 40

∴ The probability that a randomly selected student from the class is a male or a junior = Total number of favorable outcomes/Total number of outcomes = 33/40 or 0.825

Learn more about the probability of an event at

https://brainly.com/question/7965468

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