Question

A boy on a bicycle accelerates uniformly at 4.0 m/s^2 from an initial velocity of 4.0 m/s to 9.5 m/s. How long(time) does it take him to reach his final
velocity (Vf))?

Answer 1

Answer:

1.125 seconds

Step-by-step explanation:

As we know that acceleration = Final velocity- Initial Velocity

                                                          Time taken

a=v-u

     t

t=v-u

   a

In this case, Time taken= $\frac{9.5-4}{4}$

$=\frac{4.5}{4}\\=1.125$ seconds