Answer:
The answer is
[tex]x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\ [/tex]
Step-by-step explanation:
5x² + 9x + 2 = 0
Using the quadratic formula that's
[tex]x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ [/tex]
From the question
a = 5 , b = 9 , c = 2
We have
[tex]x = \frac{ - 9 \pm \sqrt{ {9}^{2} - 4(5)(2) } }{2(5)} \\ = \frac{ - 9 \pm \sqrt{81 -40 } }{10} \\ = \frac{ - 9 \pm \sqrt{41} }{10} \: \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
[tex]x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\ [/tex]
Hope this helps you