Question

M is the midpoint of cf for the points c(1,10) and f(5,6) find me to the nearest tenth

Geometry please help!!

Answer 1

Answer:

(3,8)

Step-by-step explanation:

Midpoint formula: $\frac{x_2+x_1}{2} , \frac{y_2+y_1}{2}$

$x_2$ = 5

$x_1$ = 1

$y_2$  = 6

$y_1$  = 10

$\frac{5+1}{2} , \frac{6+10}{2}$ =

$\frac{6}{2} , \frac{16}{2}$ =

(3,8)