Respuesta :

f(x)={x+5}/2-11
2x={x+5}-22
{-x+5}+2x=-22
{-x+5}=22-2x
{x+5}=22+2x
x+5=484+88x+4x^2
x+5-484-88x-4x^2=0
-87x+5-484-4x^2=0
-87x-479-4x^2=0
-4x^2-87x-479=0
4x^2+87x+479=0
x=-87+\- {87^2-4*4*479}/2*4
x=-87+\- {7569-4*4*479}/2*4
x=-87+\- {7569-7664}/2*4
x=-87+\- {7569-7664}/8
x=-87+\- {-95}/8
the square root of a negative number does not exist in the set of real numbers
x=R
*note: {xyz} means the square root*

Answer:

f(x)={x+5}/2-11

2x={x+5}-22

{-x+5}+2x=-22

{-x+5}=22-2x

{x+5}=22+2x

x+5=484+88x+4x^2

x+5-484-88x-4x^2=0

-87x+5-484-4x^2=0

-87x-479-4x^2=0

-4x^2-87x-479=0

4x^2+87x+479=0

x=-87+\- {87^2-4*4*479}/2*4

x=-87+\- {7569-4*4*479}/2*4

x=-87+\- {7569-7664}/2*4

x=-87+\- {7569-7664}/8

x=-87+\- {-95}/8

the square root of a negative number does not exist in the set of real numbers

x=R

*note: {xyz} means the square root*

Step-by-step explanation:

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