Question

Complete and balance the molecular equation for the reaction between aqueous solutions of strontium hydroxide and lithium phosphate, and use the states of matter to show if precipitate forms.

Answer 1

Answer:

Explanation:

2 Li₃(PO₄) + 3Sr(OH)₂ = Sr₃(PO₄)₂ (s) + 6LiOH

precipitate of strontium phosphate is formed.

Answer 2

The molecular equation for the reaction between aqueous solutions of strontium hydroxide and lithium phosphate is;

• 2 Li₃(PO₄) + 3Sr(OH)₂(aq) = Sr₃(PO₄)₂ (s) + 6LiOH

• The Strontium phosphate, Sr₃(PO₄)₂ is precipitated out of solution and exists as a solid.

First, we must identify the reactants and the products formed in the chemical reaction.

According to the question:

• Aqueous solutions of strontium hydroxide, Sr(OH)₂

• Lithium phosphate, Li₃(PO₄)

The reaction between the reactants above yields; Lithium hydroxide, LiOH and Strontium phosphate, Sr₃(PO₄)₂.

The balanced chemical equation is therefore;

• 2 Li₃(PO₄) + 3Sr(OH)₂(aq) = Sr₃(PO₄)₂ (s) + 6LiOH

The Strontium phosphate, Sr₃(PO₄)₂ is precipitated out of solution and exists as a solid.

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