Given:
Atul has [tex]\dfrac{2}{3}[/tex] lb of candy.
Jose has [tex]\dfrac{3}{5}[/tex] lb of candy.
Maria has [tex]\dfrac{1}{2}[/tex] lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has [tex]\dfrac{1}{2}[/tex] lb less than Jose, therefore
Maria has = [tex]\dfrac{3}{5}-\dfrac{1}{2}[/tex] lb
Maria has = [tex]\dfrac{6-5}{10}[/tex] lb
Maria has = [tex]\dfrac{1}{10}[/tex] lb
Difference between the candies Atul and Maria have.
Difference = [tex]\dfrac{2}{3}-\dfrac{1}{10}[/tex] lb
Difference = [tex]\dfrac{20-3}{30}[/tex] lb
Difference = [tex]\dfrac{17}{30}[/tex] lb
Therefore, Atul have [tex]\dfrac{17}{30}[/tex] lb of candy more than Maria.
