Question

how many total terms are there in the following sequence. 7,10,13,...,391,394

Answer 1

Answer: n = 130

Step-by-step explanation:

The sequence is an Arithmetic progression ( AP )

The last term of the sequence is (L) is 394 with the formula

L  = a + ( n- 1 )d . From the sequence, a = 7, d ( common difference ) = 3 and L ( last term ) = 394, and n = ?

Put those values in the formula above and solve for n.

  a + ( n - 1 )d =  L

  7 + ( n - 1 ) x 3  = 394

         7 + 3n - 3   = 394

             4 + 3n     = 394

                    3n     = 394 - 4

                     3n     = 390

                        n     = 130      

Answer 2

The total number of terms should be 130.

Given that,

• The series is 7,10,13,...,391,394

Based on the above information, the calculation is as follows:

We know that  

L  = a + ( n- 1 )d .

Here a = 7,

d ( common difference ) = 3

and L ( last term ) = 394, and n = ?

Now  

a + ( n - 1 )d =  L

7 + ( n - 1 ) 3  = 394

7 + 3n - 3   = 394

4 + 3n     = 394

3n     = 394 - 4

3n     = 390

n     = 130      

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