5
Type the correct answer in each box.
Functions hand k are inverse functions, and both are defined for all real numbers.
Using this relationship, what is the value of each function composition?
(h o k)(3)=
(K o h)(-46)=

5 Type the correct answer in each box Functions hand k are inverse functions and both are defined for all real numbers Using this relationship what is the value class=

Respuesta :

Answer:

(h o k)(3)=  3

(K o h)(-4b)= - 4b

Step-by-step explanation:

Composition of a function and its inverse function returns the input

(h o k)(3)=  3

(K o h)(-4b)= - 4b

Answer:

[tex](h\circ k)(3)=3[/tex]

[tex](k\circ h)(-4b)=-4b[/tex]

Step-by-step explanation:

Remember that for two functions to be inverses, the following must be true:

[tex]h(k(x))=k(h(x))=x[/tex]

Since we know they are indeed inverses, they are true.

So, whatever input we put in, we'll just get it back out again.

So, for our first problem:

[tex](h\circ k)(3)[/tex]

We can rewrite this as:

[tex]=h(k(3))[/tex]

We can imagine our x being 3 here.

Therefore, using the above identity, we can conclude that:

[tex]h(k(3))=3[/tex]

For our second example, the same thing:

[tex](k\circ h)(-4b)[/tex]

This is the same as saying:

[tex]k(h(-4b))[/tex]

Again, using the above property, we can imagine our x is -4b. So, this will be equivalent to:

[tex]k(h(-4b))=-4b[/tex]

And we're done!

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