Answer:
[tex](h\circ k)(3)=3[/tex]
[tex](k\circ h)(-4b)=-4b[/tex]
Step-by-step explanation:
Remember that for two functions to be inverses, the following must be true:
[tex]h(k(x))=k(h(x))=x[/tex]
Since we know they are indeed inverses, they are true.
So, whatever input we put in, we'll just get it back out again.
So, for our first problem:
[tex](h\circ k)(3)[/tex]
We can rewrite this as:
[tex]=h(k(3))[/tex]
We can imagine our x being 3 here.
Therefore, using the above identity, we can conclude that:
[tex]h(k(3))=3[/tex]
For our second example, the same thing:
[tex](k\circ h)(-4b)[/tex]
This is the same as saying:
[tex]k(h(-4b))[/tex]
Again, using the above property, we can imagine our x is -4b. So, this will be equivalent to:
[tex]k(h(-4b))=-4b[/tex]
And we're done!