simplify
i will give u 15 points instead of 10

Hello,
First of all , let's see that
[tex]4=2^2\leq 5\leq 9=3^2\\\\2\leq \sqrt{5}\leq 3\\ \\\text{so } (1-\sqrt{5})\leq 0\\ \\\\\text{Then } \sqrt{(1-\sqrt{5})^2}=|1-\sqrt{5}|=\sqrt{5}-1[/tex]
So,
[tex]\sqrt{6(1-\sqrt{5})^2}=\sqrt{6}(\sqrt{5}-1)=\sqrt{30}-\sqrt{6}[/tex]
Thanks