Question

g(x)=x^2+bx+11. the point (-1,8) lies on the graph of g. find the value of b.

Answer 1

Answer:

b = 4

Step-by-step explanation:

Let the given function is,

g(x) = x² + bx + 11

If a point (x, y) lies on the graph of this function, coordinates of the given point will satisfy the equation of the function.

If a point (1, 8) lies on the graph of the given function,

g(-1) = (-1)² + b(-1) + 11 = 8

1 - b + 11 = 8

12 - b = 8

b = 12 - 8

b = 4

Therefore, b = 4 will be the value of b.

Answer 2

The value of b is 4.

Given that,

• Let $g(x) =x^2+bx+11$.
• The point (-1,8) lies on the graph of g.

Based on the above information, the calculation is as follows:

Here we put -1 in place of x

So,

$g(-1) = (-1)^2 + b(-1) + 11 = 8$

1 - b + 11 = 8

12 - b = 8

b = 12 - 8

b = 4

Therefore we can conclude that the value of b is 4.

Learn more: brainly.com/question/24169758