Question

A soccer ball rolls across a field with
an initial velocity of 14.9. Due to friction, it slows down at a rate of .5 until eventually coming to a stop. How far did it roll AND how long did it take to get there?​

Answer 1

Answer:

The value is  $s = 222.01 \ m$

Explanation:

From the question we are told that

  The  initial  velocity is  $u = 14.9 \ m/s$

    The deceleration is  $a = - 0.5$

 

Generally from kinematic equations we have that

     $v^2 = u^2 + 2as$

Here v is  0 m/s because the velocity of the ball when at rest is zero so

     $0^2 = 14.9^2 + 2 (-0.5)s$

=>    $s = \frac{222.01}{1}$

=>    $s = 222.01 \ m$