Question

Compute for the pH of 0.415 M HCl acid.​

Answer 1

Answer:

The answer is

0.38

Explanation:

HCL is a strong acid and therefore undergo complete dissociation

We have

$HCL \rarr H^{ + } \: + \: Cl^{ - }$

The concentration of Hydrogen ion is also 0.415 M

The pH of a solution can be found by using the formula

$pH = - log( {H }^{ + } )$

So we have

$pH = - log(0.415) \\ = 0.381951903...$

We have the final answer as

0.38

Hope this helps you