can u show me how u get the answer

Explanation:
[tex]p1 \times v1 = p2 \times v2 [/tex]
[tex]p1 = initial \: pressure \\ v1 = initial \: volume \\ p2 = final \: pressure \\ v2 = final \: volume[/tex]
You're looking for p2. So, divide both sides by v2...
[tex] \frac{p1 \times v1}{v2} = p2[/tex]
volume of a cylinder is
[tex]h \times \pi \: \times {r}^{2} [/tex]
let's assume r = 1
[tex] \frac{p1 \times (20cm \times \pi)}{(60cm \times \pi)} = p2[/tex]
the Pi's cancel out, the 20/60 can be reduced to 1/3.
So you end up with
[tex]p1 \times \frac{1}{3} = p2[/tex]
or as the book shows....
[tex] \frac{1}{3} p[/tex]