Respuesta :

Explanation:

[tex]p1 \times v1 = p2 \times v2 [/tex]

[tex]p1 = initial \: pressure \\ v1 = initial \: volume \\ p2 = final \: pressure \\ v2 = final \: volume[/tex]

You're looking for p2. So, divide both sides by v2...

[tex] \frac{p1 \times v1}{v2} = p2[/tex]

volume of a cylinder is

[tex]h \times \pi \: \times {r}^{2} [/tex]

let's assume r = 1

[tex] \frac{p1 \times (20cm \times \pi)}{(60cm \times \pi)} = p2[/tex]

the Pi's cancel out, the 20/60 can be reduced to 1/3.

So you end up with

[tex]p1 \times \frac{1}{3} = p2[/tex]

or as the book shows....

[tex] \frac{1}{3} p[/tex]

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