Question

plz solve this if u know plz​

Answer 1

Solution:

${64}^{ - \frac{1}{3} } ( {64}^{ \frac{1}{3} } - {64}^{ \frac{2}{3} } ) \\ {64}^{ \frac{1}{3} - \frac{1}{3} } - {64}^{ \frac{2}{3} - \frac{1}{3} } \\ {64}^{0} - {64}^{ \frac{1}{3} } \\ 1 - \sqrt[3]{64} \\ 1 - 4 \\ - 3$

Answer:

$- 3$

Answer 2

Answer:

- 3

Step-by-step explanation:

Using the rules of exponents/ radicals

$a^{\frac{m}{n} }$ ⇔ $\sqrt[n]{a^{m} }$

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$

Thus

$64^{\frac{1}{3} }$ = $\sqrt[3]{64}$ = 4

$64^{-\frac{1}{3} }$ = $\frac{1}{4}$

$64^{\frac{2}{3} }$ = $\sqrt[3]{64^{2} }$ = 4² = 16

Substituting values into the given expression

$\frac{1}{4}$ (4 - 16)

= $\frac{1}{4}$ × - 12

= - 3