Question

Assume a normal distribution and that the average phone call in a certain town lasted 7 ​min, with a standard deviation of 1 min. What percentage of the calls lasted less than 6 ​min?

Answer 1

Answer:

16%

Step-by-step explanation:

First, find the z-score.

z = (x − μ) / σ

z = (6 − 7) / 1

z = -1

Use a chart, a calculator, or the empirical rule to find the probability.

Using the empirical rule:

P(Z < -1) = 0.5 − 0.34

P(Z < -1) = 0.16

Answer 2

The percentage is 16%

How do I calculate a percentage between two numbers?

To calculate the share between two numbers, divide one variety by way of the opposite and multiply the end result by way of one hundred, e.g. (30 / 75) * 100. This indicates what percent the first number is of the second one, in the example - 30 is 40% of 75.

In mathematics, a percent is more than a few or a ratio expressed as a fragment of 100. It is regularly denoted using the percentage signal, "%", although the abbreviations "pct.", "pct" and from time to time "pc" also are used. A percentage is a dimensionless number; it has no unit of size.

First, discover the z-rating.

z = (x − μ) / σ

z = (6 − 7) / 1

z = -1

Use a chart, a calculator, or the empirical rule to discover the chance.

using the empirical rule:

P(Z < -1) = 0.5 − zero.34

P(Z < -1) = 0.16

Learn more about percentages here https://brainly.com/question/26064165

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