Assuming that you start with 4.30 g of copper sulfate, how many moles of ammonia are required to completely react with this amount of of CuSO4?

Respuesta :

Answer:

Explanation:

CuSO₄(aq) + 4NH₃(aq) --> [Cu(NH₃)₄]SO₄(aq)

1 mole of copper sulphate reacts with 4 moles of ammonia

molecular weight of copper sulphate = 17 g

4.3 g of copper sulphate = 4.3 / 17 = .253 moles of copper sulphate

so with .253 moles of copper sulphate will react .253 x 4 = 1.012 moles of ammonia.

The number of moles of ammonia i.e. needed is 1.012 moles.

Calculation of the number of moles of ammonia:

The following chemical equation should be considered.

CuSO₄(aq) + 4NH₃(aq) --> [Cu(NH₃)₄]SO₄(aq)

It means that 1 mole of copper sulfate reacts with 4 moles of ammonia

Here, molecular weight of copper sulfate = 17 g

Also,

4.3 g of copper sulphate =should be

4.3 / 17

= .253 moles of copper sulphate

Now the total number of moles should be

=  .253 x 4

= 1.012 moles of ammonia.

hence, The number of moles of ammonia i.e. needed is 1.012 moles.

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