Answer:
Coefficient of friction (mu) = .42
Explanation:
In the y-direction, the only forces are normal and gravitational force, and the vertical acceleration is 0, so normal force = mg= 49 N. In the x-direction there is a positive force of 49 N and an opposing friction force which equals the friction coefficient times the normal force. Thus, we can sum the x forces and set this net force equal to ma. 50 - 49(mu)= 4.9a= 4.9(6). So mu = (50-29.4)/49= .42.
