Question

Write the equation of line in slope-intercept form:

Line parallel to y+x=3 that passes through the point (−12,0)

Answer 1

Answer:

Step-by-step explanation:

y = -x + 3

y = -(x + 12)

y = -x - 12

Answer 2

The equation in slope-intercept form of a line that passes through (-12, 0) and is parallel to y + x = 3 is: y = -x - 12

Recall:

• Parallel lines have the same slope value
• Slope-intercept form of the equation of a line is: y = mx + b.
• b = y-intercept; m = slope
• Point-slope form is: y - b = m(x - a)

The line is parallel to y + x = 3

The slope of y + x = 3 is -1

The slope of the line that is parallel to y + x = 3 will also be: -1

If the line passes through (-12, 0), write the equation in point-slope form, then rewrite in slope-intercept form by doing the following:

• Substitute (a, b) = (-12, 0) and m = -1 into y - b = m(x - a)

• Thus

y - 0 = -1(x -(-12))

y = -1(x + 12)

y = -x - 12

Therefore, the equation in slope-intercept form of a line that passes through (-12, 0) and is parallel to y + x = 3 is: y = -x - 12

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