Question

√3 /√6 rationalise denominator and simplify

Answer 1

Answer:

$\frac{ \sqrt{2} }{2}$

Step-by-step explanation:

$\frac{ \sqrt{3} }{ \sqrt{6} } \\ \frac{ \sqrt{3} }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } \\ \frac{ \sqrt{3 \times 6} }{ \sqrt{ {6}^{2} } } \\ \frac{ \sqrt{18} }{6} \\ \frac{ \sqrt{2 \times 9} }{6} \\ \frac{3 \sqrt{2} }{6} \\ \frac{ \sqrt{2} }{2}$

Answer 2

Answer:

⇛√2/2.

Step-by-step explanation:

Given that,

√3/√6

The denominator is √6

We know that

The rationalising factor of √a is √a

Therefore, the rationalising factor of √6 is '√6’.

Now,

⇛(√3/6) × (√6/√6)

⇛{√3(√6)}/(√6)(√6)

⇛(√3*6)/(√6)²

⇛(√18)/(6)

⇛(√2*9)/6

⇛(2√2)/6

⇛√2/2

Hence, the denominator is rationalised.